f(x) = P1x^n-1 + P2x^n-2 +... + Pn-1x +Pn (eq10.25)
where the p's are constant coefficients. A straightforward way for computing the coefficients is to generate n linear algebraic equations that we can solve simultaneously for the coefficients. Suppose that we want to determine the coefficients of the fourth-order polynomial f(x) = p1x^4 + p2x^3 +p3x^2 +p4x +p5 that passes through the following five points:(200,0.746),(250, .675), (300,.616), (400, .525) and (500, .457). Each of these pairs can be substituted into Eq. (P10.25) to yield a system of five equations with five unknowns (the p's). Use this approach to solve for the coefficients. In addition, determine and interpret the condition number.
Matlab code:
B = [ .746; .675; .616; .525; .457]
x = [200, 250, 300, 400, 500];
xx = [1,1,1,1,1];
A = [ x.^4 ;x.^3; x.^2 ;x.^1; xx]'
p = A\B
A * p
cond(A)
RESULTS
B =
7.4600e-01
6.7500e-01
6.1600e-01
5.2500e-01
4.5700e-01
A =
1.6000e+09 8.0000e+06 4.0000e+04 2.0000e+02 1.0000e+00
3.9062e+09 1.5625e+07 6.2500e+04 2.5000e+02 1.0000e+00
8.1000e+09 2.7000e+07 9.0000e+04 3.0000e+02 1.0000e+00
2.5600e+10 6.4000e+07 1.6000e+05 4.0000e+02 1.0000e+00
6.2500e+10 1.2500e+08 2.5000e+05 5.0000e+02 1.0000e+00
p =
1.3333e-12 P1
-4.5333e-09 P2
5.2967e-06 P3
-3.1737e-03 P4
1.2030e+00 P5
ans =
7.4600e-01
6.7500e-01
6.1600e-01
5.2500e-01
4.5700e-01
cond(A) =
1.1712e+13
A has a large condition number, meaning it is ill-formed, and there is a high potential for error
No comments:
Post a Comment